Drawing the Lewis Structure for BrF5

Viewing Notes:

  • In the BrF5 Lewis structure, Bromine (Br) is the least electronegative atom and goes in the center of the Lewis structure.
  • For the BrF5 Lewis structure, you'll need to put more than eight valence electrons on the Bromine atom.
  • In the Lewis structure for BrF5 there are a total of 42 valence electrons.

Transcript: This is the BrF5 Lewis structure. For BrF5, we have a total of 42 valence electrons. Bromine is the least electronegative, we'll put that in the center and then we'll put 5 Fluorines around the outside. We'll draw single bonds between the atoms for a total of 5 single bonds, so 10 valence electrons. Then we'll go around the outside, 12, and complete the octets for Fluorine: 14, 16, and 40.

So we've used 40 valence electrons. The Fluorines all have octets. But we have 42, so we have 2 additional valence electrons. We're just going to put those right here on the Bromine. Bromine is in period 4 on the periodic table, and it can have more than 8 valence electrons. If you were to check the formal charges for this structure, you'd see that the formal charge for each atom in BrF5 is zero.

So this is the Lewis structure for BrF5. This is Dr. B., and thanks for watching.